analysis - History of convolution - Mathematics Stack Exchange The convolution has a nice property, when Fourier transformed: $$ \mathcal{F}(f*g) = c \, \mathcal{F}(f) \mathcal{F}(g) $$ for some constant specific to the definition of the Fourier transform used And it is the continous cousin of the Cauchy product
Convolution $f*g$ is continuous - Mathematics Stack Exchange Stack Exchange Network Stack Exchange network consists of 183 Q A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers
Derivative of convolution - Mathematics Stack Exchange Stack Exchange Network Stack Exchange network consists of 183 Q A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers
real analysis - On the closedness of $L^2$ under convolution . . . Stack Exchange Network Stack Exchange network consists of 183 Q A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers
real analysis - Convolution of two gaussian functions - Mathematics . . . You should end up with a new gaussian : take the Fourier tranform of the convolution to get the product of two new gaussians (as the Fourier transform of a gaussian is still a gaussian), then take the inverse Fourier transform to get another gaussian $\endgroup$ –