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  • D. Helium effuses 4 times faster than sulphur dioxide. - Socratic
    Which is true about the effusion rates of helium and sulphur dioxide when the molar mass of helium is 4 grams mole and the molar mass of sulphur dioxide is 64 grams? A Sulphur dioxide effuses 4 times faster than helium
  • The density of a Gas is 1. 43 g mol at STP. What is the gas . . . - Socratic
    Now, the answer is indeed oxygen gas, "O"_2, because that's the closest match in terms of the molar mass M_ ("M O"_2) = "31 9988 g mol" Sulfur has a molar mass of M_ ("M S") = "32 065 g mol" but it cannot be a match here because sulfur is not a gas at STP conditions -> see here for info on the boiling point of sulfur at a pressure of "1 atm"
  • Question #928a6 - Socratic
    The reaction produces 3 60 mol or "82 dm"^3color(white)(l) "of N"_2 > Step 1 Write the balanced chemical equation The balanced equation is "2NaN"_3 → "2Na" + "3N"_2 Step 2 Strategy The problem is to convert grams of "NaN"_3 to moles of "N"_2 and volume of "N"_2 We can use the flow chart below to help us (Adapted from www lsua us) The process is: (a) Use the molar mass to convert the
  • Question #75aa6 - Socratic
    Sulfur dioxide, or #SO_2#, will react with oxygen gas, or #O_2#, to form sulfur trioxide, or #SO_3#, according to the balanced chemical equation
  • Determination of the relative molecular mass of compound (a . . . - Socratic
    Mass of compound A: Sample 1: 0 3398 g Sample 2: 0 3322 g Volume of sulfamic acid solution: Sample 1: #"35 36 cm"^3# Sample 2: #"32 90 cm"^3# Need to work out for both samples: Moles of NaOH solution Moles of compound A #"Molecular Weight of A g·mol"^"-1"# Average Molecular weight of A And the Melting point of compound A is 122-177 °C
  • Question #ebf5e + Example - Socratic
    The molar mass of citric acid is 192 12 g, so 0 00067 moles is 192 12 x 0 00067 = 0 1287 g of citric acid The % of citric acid was therefore: #(0 1287 120) 100 = 0 1073%# Please note that, with the exception of the reaction equation and the molar mass, I just made these numbers up to illustrate the procedures - I can't recall how much citric acid is really in orange juice!
  • How many moles are there in 45 g of Neon? - Socratic
    Approx 11 4 moles Neon, Z=18, has an equivalent mass of 20 18 g*mol^-1 To find the molar quantity
  • Question #5b97a + Example - Socratic
    Here's what I got I don't think that you have enough information to provide a numerical solution, but you can find the mass of the gas that was released from the container in terms of P_(rho), the pressure at which the density of the gas is equal to "0 78 g L"^(-1) The first thing that you need to do here is to use the density of the gas, rho, to find its molar mass, let's say M_M, in terms
  • Question #68773 - Socratic
    We can determine the mass of any number of moles of a given substance by using that substance's molar mass The molar mass represents the mass of exactly #1# mole of a substance In this case, carbon dioxide has a molar mass of #color(blue)("44 0 g")# #color(darkorange)("mol"^(-1))# This means that #color(darkorange)(1)# mole of carbon dioxide
  • How do you calculate the number of grams in 0. 865 moles?
    As written I can you tell you how many particles there are in 0 865 moles, but NOT the number of grams The mole is a collective number like a dozen, or a gross, or a score, etc Admittedly it is a very large collective number If I have a mole of stuff, I have 6 022xx10^23 individual items of stuff Why should we pick such an absurdly large number? Well it happens that 6 022xx10^23 individual





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