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  • What’s the difference between EAX, EBX, and ECX in assembly?
    eax, ebx, ecx and so on are actually registers, which can be seen as "hardware" variables, somewhat similar to higher level-language's variables Registers can be used in your software directly with instructions such as mov, add or cmp
  • assembly - How do AX, AH, AL map onto EAX? - Stack Overflow
    So AX is composed of AH:AL halves, and is itself the low half of EAX (The upper half of EAX isn't directly accessible as a 16-bit register; you can shift or rotate EAX if you want to get at it ) x86-64 CPUs extend the integer registers to 64-bit: RAX is the full 64-bit value, with EAX and its sub-components mapped to the lower 32 bits The
  • Dashboard EAX - Forex Factory
    Latest EAX update (on a fresh setup install prerequisites first) Inserted Code DBMASMEAX007a3 bundle3 rev update 013 7 5 (20220615): …expiring in 2023 12 31 23:59:59 GMT !
  • assembly - The point of test %eax %eax - Stack Overflow
    TEST EAX,EAX JE some_address the CPU will jump to "some_address" if and only if ZF = 1, in other words if and only if AND(EAX,EAX) = 0 which in turn it can occur if and only if EAX == 0 the equivalent C code is:
  • What does the bracket in `movl (%eax), %eax` mean?
    MOV sets EAX = the value from memory at that address Your re-phrasing of the existing answer isn't adding anything new, and is actually less clear because you're mis-using "address" to mean "memory at that address", which is the opposite of what "address" normally means
  • c - Why is eax used on 64-bit? - Stack Overflow
    %eax refers to the lower 32 bits of the 64-bit %rax register So, if %rax is initially 0, and you execute the instruction movl $5, %eax, then %rax will also take on the value 5 However, they are not entirely independent, so one should be careful
  • assembly - How is rax different from eax? - Stack Overflow
    Registers like eax, ebx, etc are the 32-bit registers which exist both in the original 32-bit x86 ISA, as well as the 64-bit x86-64 If your book refers only to those registers, it is likely that it doesn't cover the 64-bit extension (perhaps it was written before it)
  • Why would one use movl $1, %eax as opposed to, say, movb $1, %eax
    %eax is not zeroed out unless you either movl $0, %eax, or if you xorl %eax, %eax Otherwise it holds whatever value was previously in there When you movl $1, %eax, you will end up with 0x00000001 in the register because the 32-bit instruction moves a 32-bit immediate value into the register
  • How should I understand usage of %eax register in assembly code?
    Can I change %eax to %rax at the second line of assembly code? Yes, and it would likely generate exactly the same instruction It might generate an instruction with a REX prefix which does the same thing (so a 1-byte larger instruction) You could also use xor %eax, %eax or xor %rax, %rax for the same effect





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