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  • What does the assignment of ~0u to a variable mean in C++?
    Thus ~0u means the maximum value of an object of type unsigned int when each bit of its internal representation is set to 1 Consider using the operator that to set for example the first n bits to 1 The expression will look like ~( ~0u << n ) If you want to set n bits starting from m position then you can write ~( ~0u << n ) << m
  • c - What does u mean after a number? - Stack Overflow
    unsigned int x = 0u; This can lead to a situation where developers that deal a lot with unsigned values develop the habit of adding u suffixes to literals everywhere But, be aware that changing signedness can lead to different behavior in various contexts, for example: (x > 0) can (depending on the type of x) mean something different than (x > 0u)
  • c# - Difference between 0 and 0u - Stack Overflow
    The uint type is 32-bit unsigned integer type Its default value is the number 0u or 0U (the two are equivalent) The 'u' letter indicates that the number is of type uint (otherwise it is understood as int) Then is there a difference between 0 and 0u? If not, then why is the default value '0u'
  • c++ - Meaning of U suffix - Stack Overflow
    @Ela782: Yep I am not sure off the top of my head, but without the u it could well be a signed long long
  • c - What do 0LL or 0x0UL mean? - Stack Overflow
    I am reading the Google Go tutorial and saw this in the constants section: There are no constants like 0LL or 0x0UL I tried to do a Google search but all that comes up are instances where people
  • c++ - What does (1U lt; lt; X) do? - Stack Overflow
    I found this piece of code: enum { IsDynamic = (1U << 0), IsSharable = (1U <; lt; 1),
  • What does 0u mean in c#? - Stack Overflow
    Much like 0L defines 0 as a long, 0u defines 0 as an unsigned int (uint) Share Improve this
  • c - #define FOO 1u 2u 4u . . . What does 1u and 2u mean . . . - Stack Overflow
    I'm working with the HCS12 MCU, and this was part of the library I'm just wondering what the 1U, 2U, 4U, 8U means in this code I'm still learning how to use classes, please try to explain thi
  • c - Why (uint8)0U appears to the static code analysis tool as a . . .
    0U has type unsigned int and (uint8)0U has type unsigned char, but like all types smaller than int, it gets promoted to int in an expression context such as an operand to ~ You should just remove the cast and use ~0U Note however that on systems with 16- or 32-bit ints using two's complement representation (almost all current systems *):
  • Whats the point in specifying unsigned integers with U?
    Here's my answer, (in bold, for those who only want a quick answer): There's really no good reason to declare a constant as 10U or 0U Most of the time, you're within the common range of uint and int, so the value of that constant looks exactly the same whether its a uint or an int





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